6,966,006
2 × 3 × 1161001
Abundant
Even
Composite
6,966,006 factors as 2 × 3 × 1161001. Its 8 positive divisors give a proper-divisor sum of 6,966,018, so this integer is abundant. The Collatz stopping time is 129 steps.
Prime Factor Structure
Factorization String
2 × 3 × 1161001
Distinct Prime Factors
3
Square Status
No
Abundance Measure
Abundant
Analytical Properties
Total Divisors
8
Divisor Sum (σ)
13,932,024
Proper Divisor Sum
6,966,018
Digit Sum / Digital Root
33 (Root: 6)
Adjacent Primes
#6965977 ← → #6966007
Radix Representation
| Decimal | 6966006 |
| Binary | 11010100100101011110110 (23 bits) |
| Octal | 0o32445366 |
| Hexadecimal | 0x6A4AF6 |
Divisor Catalog (8)
Collatz Trajectory (129 steps to reach 1)
Iterative sequence n → n/2 (if even) or 3n+1 (if odd):