1,041,090
2 × 3 × 5 × 34703
Abundant
Even
Composite
1,041,090 factors as 2 × 3 × 5 × 34703. Its 16 positive divisors give a proper-divisor sum of 1,457,598, so this integer is abundant. The Collatz stopping time is 165 steps.
Prime Factor Structure
Factorization String
2 × 3 × 5 × 34703
Distinct Prime Factors
4
Square Status
No
Abundance Measure
Abundant
Analytical Properties
Total Divisors
16
Divisor Sum (σ)
2,498,688
Proper Divisor Sum
1,457,598
Digit Sum / Digital Root
15 (Root: 6)
Adjacent Primes
#1041083 ← → #1041091
Radix Representation
| Decimal | 1041090 |
| Binary | 11111110001011000010 (20 bits) |
| Octal | 0o3761302 |
| Hexadecimal | 0xFE2C2 |
Divisor Catalog (16)
Collatz Trajectory (165 steps to reach 1)
Iterative sequence n → n/2 (if even) or 3n+1 (if odd):